Ecuația de stare a gazelor

[invite125ec1b7]

Ce volum ocupă,la 327 grade Celsius și 300 atm, 2800kg de azot molecular? Mulțumesc anticpat pentru ajutor.
-----

[Kemiste]

Et en français ça donne quoi?

[invite125ec1b7]

Quelle est la charge à 327 degrés Celsius et de l'azote moléculaire 300 atm de 2800 kg? Anticpat Merci pour votre aide.

[Kemiste]

C'est du google translate ça... Quelle est la question? Quel est ton problème? Parles-tu français?

[A voir en vidéo sur Futura]

[invite125ec1b7]

Sorry, I dont speak French very well.I translated the problem with Google translate.My problem is:Which is the volume of 2800 kg of Nitrogen,which has the temperature
327 Celsius degrees and the pressure 300 atm.

[Kemiste]

Ok. Maybe with the ideal gas law?

PS : c'est un forum français...

[invite125ec1b7]

I dont know...I tried but it didnt worked...Can you,please,explain me a little bit detailed?

[Kemiste]

Why do you say it didn't work? What did you do? What are your results?

Ideal gas law : PV = nRT. You know P, R, T and you can know n (you kwnow the weight of nitrogen)

[invite125ec1b7]

I tried: T=327 Celsius degrees=600 K. degrees.
300 atm V=14x0,082x600
V=688,8/300
V=2,29 and the correct that is written in manual is 16,4.

[Kemiste]

I tried: T=327 Celsius degrees=600 K. degrees.
300 atm V=14x0,082x600
V=688,8/300
V=2,29 and the correct that is written in manual is 16,4.

There is a mistake. What is 14? There is 2800 kg of N₂, so how many mol?
With the right number of moles you will find the right volume.

[HarleyApril]

PS : c'est un forum français...

Da, este un loc în care suntem obișnuiți să scrie în franceză

[invite125ec1b7]

Da,dar unii poate au nevoie de ajutor si nu cunosc foarte bine franceza...asa ca pot scrie doar în română sau engleză.Engleza este o limbă internațională,si cunoscuta de toti.

[Kemiste]

@ HarleyApril Lucrurile se schimba...

[JPL]

Discussion fermée.